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用API函数打开公用对话框
作  者:汉南居士
关键字:VB-API函数



在模块中加入:
Declare Function GetOpenFileName Lib "comdlg32.dll" Alias "GetOpenFileNameA" (pOpenfilename As- OPENFILENAME) As Long
Type OPENFILENAME
     lStructSize As Long
     hwndOwner As long
     hInstance As Long
     lpstrFilter As String
     lpstrCustomFilter As String
     nMaxCustFilter As Long
     nFilterIndex As Long
     lpstrFile As String
     nMaxFileTitle As Long
     lpstrInitialDir As String
     lpstrTitle As String
     flags As Long
     nFileOffset As Integer
     nFileExtension As Integer
     lpstrDefExt As String
     lCustData As Long
     lpfnHook As Long
     lpTemplateName As String
End Type
   然后在Form窗体上加一个文本框和按钮Caption属性为"打开".双击按钮加入下列代码:
Private Sub Command1_Click()
      Dim ofn As OPENFILENAME
      Dim rtn As String
      ofn.lStructSize=len(ofn)
      ofn.hwndOwner=Me.hWnd
      ofn.hInstance=App.hInstance
      ofn.lpstrFilter="所有文件"
      ofn.lpstrFile=Space(254)
      ofn.nMaxFileTitle=255
      ofn.lpstrInitialDir=app.path
      ofn.lpstrTitle="打开文件"
      ofn.flags=6148
      rtn=GetOpenFileName(ofn)
      If rtn>=1 then
          Text1.Text=ofn.lpstrFile
      Else
          Text1.Text="Cancel Was Pressed"
      End If
End Sub
     运行程序,点击"打开"按钮就会弹出打开文件对话框.选中任何文件再确定,Text1.Text就会显示任何文件名。


来源:互联网
阅读:489
日期:2005-11-20

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